«Confetti 3a: Game of Life» by henklass
on 14 May'15 17:38 inIt is relatively simple to convert Confetti3 ( http://sccode.org/1-4YU )to John Conway's Game of Life. You just need to change the rules and make sure that any creature that runs of the board returns at the other side. It may be a good idea to speed things a bit up. This may be achieved by using the Xenakis-inspired version: http://sccode.org/1-4YW .
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116
s.boot; ( var maxWidth=15, maxHeight = 15; var z=40, ready = false; var newValues=Array2D.new(maxWidth + 2, maxHeight + 2); var oldValues=Array2D.new(maxWidth + 2, maxHeight + 2); var go, total; /*There is a decreasing linear connection between log(freq) and location in array: h+(maxWidth*v). Highest location-value in array = maxWidth*maxHeight log(freq)=log(maxfreq)-((log(maxfreq)-log(minfreq))*(h+(maxWidth*v))/(maxWidth*maxHeight), so freq=exp(log(maxfreq)-((log(maxfreq)-log(minfreq))*(h+(maxWidth*v))/(maxWidth*maxHeight) Furthermore freq depends on value, which is either 0 or 1. freq=freq+(freq*value) or freq=(1+value)*freq Combining those 2: freq=(exp(log(maxfreq)-((log(maxfreq)-log(minfreq))*(h+(maxWidth*v))/(maxWidth*maxHeight))*(1+value) */ SynthDef(\beeper, { arg h, v, p, maxWidth, maxHeight; var maxfreq=5000, minfreq=50; Out.ar( 0, Pan2.ar( Pulse.ar(exp(log(maxfreq)-((log(maxfreq)-log(minfreq))*(h+(maxWidth*v))/(maxWidth*maxHeight)))*(1+p), 0.5, 0.3), 2*h/maxWidth-1, //pan depends on column in array 1 ) ); }).add; w=Window("Confetti3", Rect(400, 300, z*(maxWidth+2), z*(maxHeight+2))).front; w.view.background_(Color.white); w.front; w.drawFunc = { for (1, maxHeight, {arg v; for (1, maxWidth, {arg h; if (newValues[h,v]==0, {Pen.fillColor=Color.white}, {Pen.fillColor=Color.black} ); Pen.addRect(Rect(h*z, v*z, z, z)); Pen.fill; }); }); }; go=Routine({ //make random pattern for (1, maxWidth, {arg h; for (1, maxHeight, {arg v; newValues[h,v]=[0, 1].choose; {w.refresh}.defer; p=newValues[h,v]; b=Synth("beeper",[p: p, h: h, v: v, maxWidth: maxWidth, maxHeight: maxHeight]); 0.1.wait; b.free; }) }); while ({ready==false},{ //copy edges of board to edges of array for(1, maxWidth, {arg h; newValues[h,0]=newValues[h, maxHeight]; newValues[h, maxHeight+1]=newValues[h, 1]; }); for(1, maxHeight, {arg v; newValues[ 0, v]=newValues[maxWidth, v]; newValues[maxWidth+1, v]=newValues[1, v]; }); newValues[0,0]=newValues[maxWidth, maxHeight]; newValues[0, maxHeight+1]=newValues[maxWidth, 1]; newValues[maxWidth+1, 0]=newValues[1, maxHeight]; newValues[maxWidth+1, maxHeight+1]=newValues[1,1]; //copy newValues to oldValues (including edges) for (0, maxWidth+1, {arg h; for (0, maxHeight+1, {arg v; oldValues[h,v]=newValues[h,v]; }) }); //adapt for (1, maxWidth,{arg h; for (1, maxHeight, {arg v; total=oldValues[h-1,v-1] + oldValues[h,v-1] + oldValues[h+1,v-1] + oldValues[h-1,v]+ oldValues[h+1,v] + oldValues[h-1,v+1] + oldValues[h,v+1] + oldValues[h+1,v+1]; if( (total<=1 )|| (total > 3), {newValues[h,v]=0} ); if( total==3, {newValues[h,v]=1} ); {w.refresh}.defer; if (newValues[h,v]!=oldValues[h,v],{ p=newValues[h,v]; b=Synth("beeper",[p: p, h: h, v: v, maxWidth: maxWidth, maxHeight: maxHeight]); 0.1.wait; b.free; }); }) }); //check if ready ready=true; for (1, maxWidth,{arg h; for (1, maxHeight, {arg v; if (oldValues[h,v]!=newValues[h,v], {ready=false}); }) }); }); }); go.play; )
reception
comments